Preface
This is a tutorial made solely for the purpose of education and it was designed for students taking Applied Math 0330. It is primarily for students who have very little experience or have never used Mathematica before and would like to learn more of the basics for this computer algebra system. As a friendly reminder, don't forget to clear variables in use and/or the kernel.
Finally, the commands in this tutorial are all written in bold black font, while Mathematica output is in regular fonts. This means that you can copy and paste all comamnds into Mathematica, change the parameters and run them. You, as the user, are free to use the scripts to your needs for learning how to use the Mathematica program, and have the right to distribute this tutorial and refer to this tutorial as long as this tutorial is accredited appropriately.
Return to computing page for the second course APMA0340
Return to Mathematica tutorial for the second course APMA0330
Return to Mathematica tutorial for the first course APMA0340
Return to the main page for the course APMA0340
Return to the main page for the course APMA0330
Return to Part II of the course APMA0330

Riccati Equations
Jacopo Francesco Riccati (1676-1754) was an Venetian mathematician and jurist from Venice. He is best known for having studied the differential equation which bears his name:
When h(x) = 0, we get a Bernoulli equation. The Riccati equation has much in common with linear equations; for example, it has no singular solution. Except special cases, the Riccati equation cannot be solved analytically using elementary functions or quadratures, and the most common way to obtain its solution is to represent it in series. Moreover, the Riccati equation can be reduced to the second order linear differential equation by substitution
Theorem (Liouville, 1841). The special Ricacti equation \( y' = a\,y^2 + b\, x^{\alpha} \) can be integrated in closed form if and only if
The special Ricacti equation can be represented as \( y' = -u' /(au) , \) where
Example: The Riccati equation
Example: Consider the Riccati equation
It can be solved by substitution y =x^2 +1/v(x) , where y1=x^2 is a particular solution of the given Riccati equation.
y1[x_] = x^2
R[x, y1]
Simplify[Expand[v[x]^2 R[x, Function[t, t + t/v[t]]]]]
DSolve[% == 0, v[x], x] (* solve linear equation for v *)
y2[x_] = Simplify[(y1[x] + 1/v[x]) /. %[[1]]]
Out[12]= x^2
Out[13]= 0
Out[14]= -(1 + 2 x^2) v[x] + (-1 - x^2 + x^4) v[x]^2 - x (x + Derivative[1][v][x])
Out[15]= {{v[x] -> -(x (-(E^((2 x^3)/3 - 1/6 x^2 (3 + 2 x))/(2 x)) + (
E^((2 x^3)/3 - 1/6 x^2 (3 + 2 x)) (1 + x))/(2 x^2) - (
E^((2 x^3)/3 - 1/6 x^2 (3 + 2 x)) (1 + x) ((5 x^2)/3 - 1/3 x (3 + 2 x)))/(
2 x) + (-((E^(-(1/6) x^2 (3 + 2 x)) (-1 + x))/x^2) +
E^(-(1/6) x^2 (3 + 2 x))/x + ( E^(-(1/6) x^2 (3 + 2 x)) (-1 + x) (-(x^2/3) -
1/3 x (3 + 2 x)))/x) C[1]))/((-1 - x^2 + x^4) (-((E^((2 x^3)/3 - 1/6 x^2 (3 + 2 x)) (1 + x))/(
2 x)) + (E^(-(1/6) x^2 (3 + 2 x)) (-1 + x) C[1])/x))}}
Out[16]= (E^((2 x^3)/3) (-1 - x + x^2) + 2 (-1 + x + x^2) C[1])/(E^((
2 x^3)/3) + 2 C[1])
First Order ODEs
Plotting Solutions to ODEs
Direction Fields
Separable Equations
Equations Reducible to the Separable Equations
Equations with Linear Fractions
Exact Equations
Integrating Factors
Linear Equations
RC circuits
Bernoulli Equations
Riccati Equations
Existence and Uniqueness
Qualitative Analysis
Bifurcations
Orthogonal Trajectories
Population Models
Applications
Return to Mathematica page
Return to the main page (APMA0330)
Return to the Part 1 (Plotting)
Return to the Part 2 (First Order ODEs)
Return to the Part 3 (Numerical Methods)
Return to the Part 4 (Second and Higher Order ODEs)
Return to the Part 5 (Series and Recurrences)
Return to the Part 6 (Laplace Transform)