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Three-Dimensional Galerkin Convective Operator Spectrums

We will now consider the same problem posed in three-dimensions. Each element type will be shown to have different spectral properties. The three-dimensional linear convective equation for u(x,y,z,t) is:

\begin{displaymath}
\frac{\partial u(x,y,z,t)}{\partial t} + Lu \equiv 
\frac{\p...
 ...z)\diff{u}{x} + b(x,y,z)\diff{u}{y} + c(x,y,z)\diff{u}{z} = 0. \end{displaymath}

We consider the variational form of this equation in $\Omega^k$, that is:

Find $u \in H^1(\Omega)$ such that for all $w \in H^1(\Omega)$

\begin{displaymath}
\left(\frac{\partial u}{\partial t} + a\frac{\partial u}{\pa...
 ...tial z},w\right) = 0, \hspace{12pt} \forall w \in H^1(\Omega). \end{displaymath}

Applying the Galerkin formulation so that the trial and test spaces are spanned by the same basis we obtain:

\begin{displaymath}
\left( \phi_n, \phi_m \right) \frac{d \hat{u}_m}{dt} = 
\lef...
 ... \frac{\partial \phi_m}{\partial z} \right)
 \right] \hat{u}_m \end{displaymath}

We now define two local operators Bk and $L_k(\theta)$:

where we have normalized the convection velocity appropriately so that its direction $\theta$ is defined by the scalars a,b.

Based on these definitions we now construct two new operators for the entire domain:

\begin{displaymath}
L(\theta) = \left[\begin{array}
{cccc}
 L_1 & 0 & ... & 0 \...
 ..... & ... & ... & ... \  0 & 0 & ... & L_K
 \end{array} \right]\end{displaymath}

and similarly:

\begin{displaymath}
B = \left[\begin{array}
{cccc}
 B_1 & 0 & ... & 0 \  0 & B_...
 ... & ... & ... & ... \  0 & 0 & ... & B_K
 \end{array} \right]. \end{displaymath}

As in the two-dimensional case (section 4.3) we assemble the boundary degrees of the freedom to make the operator act continuously across the element interfaces. This time the Z operator maps the globally numbered modes to the locally numbered vertex, edge and face modes.



T. Warburton
10/24/1998